9 ABCD is a rectangle with AB = 10 cm and AD = 12 cm. PQ is parallel to AB and RS is parallel to AD. Y is the point of intersection of PQ and RS. BR = DP = x cm. A smaller rectangle and a square are shaded. (a) Write down an expression, in terms of x, for (i) AR, (ii) AP. (b) Area of shaded rectangle ARYP/Area of rectangle ABCD =3/4 Show that x^2 -22x+30 = 0. (c) Solve the equation x^2 -22x+30 = 0. Show your working and give your answers correct to 2 decimal places.